测试评估
| 指标 | 结果 |
|---|---|
| Base 测试 | PASS |
| Plus 测试 | PASS |
| 代码长度 | 454 字符 |
模型生成的代码 （454 字符）
def count_char_position(s: str) -> int:
"""
Count the number of characters in a string that occur at the same position
in the string as in the English alphabet (case insensitive).
"""
count = 0
for i, ch in enumerate(s):
# Position in the alphabet (1-based)
alpha_pos = ord(ch.lower()) - ord('a') + 1
# Position in the string (1-based)
if alpha_pos == i + 1:
count += 1
return countBase 失败测试用例
- 无失败测试
Plus 失败测试用例
- 无失败测试