测试评估
| 指标 | 结果 |
|---|---|
| Base 测试 | PASS |
| Plus 测试 | FAIL |
| 代码长度 | 719 字符 |
模型生成的代码 （719 字符）
from typing import List, Any
def is_samepatterns(seq1: List[Any], seq2: List[Any]) -> bool:
"""
Returns True if seq1 and seq2 follow the same pattern, i.e., the equality
relationships among elements are identical. For example:
["red","green","green"] and ["a","b","b"] both have the pattern (0,1,1).
"""
if len(seq1) != len(seq2):
return False
# Build normalised pattern: list of indices of first occurrence
def pattern(seq: List[Any]) -> List[int]:
seen = {}
pat = []
for item in seq:
if item not in seen:
seen[item] = len(seen)
pat.append(seen[item])
return pat
return pattern(seq1) == pattern(seq2)Base 失败测试用例
- 无失败测试
Plus 失败测试用例
[['red', 'red', 'red', 'red', 'red', 'red'], ['a', 'b', 'c', 'a', 'b', 'c']]