测试评估
| 指标 | 结果 |
|---|---|
| Base 测试 | PASS |
| Plus 测试 | PASS |
| 代码长度 | 579 字符 |
模型生成的代码 （579 字符）
def find_dissimilar(tup1, tup2):
"""
Return a tuple of elements that appear in exactly one of the two input tuples.
The order is: first the elements unique to tup1 (in their original order),
followed by the elements unique to tup2 (in their original order).
"""
set2 = set(tup2)
set1 = set(tup1)
# Elements in tup1 not in tup2, preserving order
unique_tup1 = [x for x in tup1 if x not in set2]
# Elements in tup2 not in tup1, preserving order
unique_tup2 = [x for x in tup2 if x not in set1]
return tuple(unique_tup1 + unique_tup2)Base 失败测试用例
- 无失败测试
Plus 失败测试用例
- 无失败测试