测试评估
| 指标 | 结果 |
|---|---|
| Base 测试 | PASS |
| Plus 测试 | FAIL |
| 代码长度 | 362 字符 |
模型生成的代码 （362 字符）
def find_Odd_Pair(arr, n):
"""
Count the number of pairs (i, j) in arr such that arr[i] ^ arr[j] is odd.
Since XOR is odd iff the two numbers have different parity,
the answer is (#odd) * (#even).
"""
odd_count = sum(1 for x in arr if x % 2 != 0)
even_count = n - odd_count # or len(arr) - odd_count
return odd_count * even_countBase 失败测试用例
- 无失败测试
Plus 失败测试用例
[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 1]